If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2=4=-12x
We move all terms to the left:
9x^2-(4)=0
a = 9; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·9·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*9}=\frac{-12}{18} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*9}=\frac{12}{18} =2/3 $
| Y=-64x+169 | | 3x+2=5(x-6) | | 4+h=-3 | | -390+x=-56 | | -(g+-5)+-15=-3 | | -35g=12 | | 2-5x=x+2 | | -6(6+3n)=3(3-3n) | | x^2-30x+225=400 | | -3(3x-2)+7(x+3)=6+3x-8x | | -4(1-b)=-2(6b+2)+b | | 4(2t+2)-15t=22 | | |4x+1|=11 | | 10.5s+9.77=-19.93-13.8s | | -x-22=-3+18 | | 4/3w-12= | | -5(-1-2r)+5=6(r+1) | | (-5a)-(-7a)+(-6a)=-12 | | F(x)=42+1.4x | | -3(3a+4)=3(1+2a) | | -3(3x-2)+7(x+3)=6+3x-8 | | 2(x+4)+2(x-2)=x+3+x+5+x+4 | | .9x+3.2=-1.7x | | -v+3/2v=4/3 | | -3(x-1)=2(3-3x) | | 4m-3-8m+1=-5m+9 | | 12.69+13.7k-11.66=13k-12.76 | | 6v-3(5v-3)=2-9v | | 35+6n=n-5(1-5n) | | 1.12+2.5x=2.7+.7 | | 7t–8=5t | | -5(1+m)=2(2-m) |